How can I tell whether or not a molecule is planar?
Otherwise, its structure allows it to be planar. Even though the molecule will have a structure that allows for it to exist in a planar conformation, there may be some/many that do not persist in a planar …
Difference between radial, planar, angular and spherical nodes
Mar 26, 2015 · Does this mean that all p orbitals have planar nodes and in d, only dz2 d z 2 has conical node while others have planar node. I am clear about radial/spherical nodes. Thanks.
inorganic chemistry - How to use crystal field theory to predict ...
How can one predict whether a given complex ion will be square planar or tetrahedral when its coordination number is 4 using crystal field theory? Is it possible to theoretically predict this?
Why is [PdCl4]2- square planar whereas [NiCl4]2- is tetrahedral?
The molecule $\ce { [PdCl4]^2-}$ is diamagnetic, which indicates a square planar geometry as all eight d electrons are paired in the lower-energy orbitals. However, $\ce { [NiCl4]^2-}$ is also $\mathr...
Why is the crystal field splitting energy larger for square planar than ...
May 16, 2020 · 1 It is because of the fact that square planar complexes are formed by much strong ligands with d8-metal cation of 3d- series transition metals cation and 4d or 5d-series transition metal …
Why is biphenyl not planar? - Chemistry Stack Exchange
Jun 9, 2020 · I've seen in a lot of books that biphenyl is not planar. I don't know why that is because both the carbon are $\\mathrm{sp^2}$ hybridized so it should be planar. Can someone explain it to me?
inorganic chemistry - Why is (NH4)2 [CuCl4] square planar complex but ...
Sep 1, 2016 · Why is $\ce { (NH4)2 [CuCl4]}$ square planar complex but $\ce {Cs2 [CuCl4]}$ is tetrahedral even though both have same oxidation number of copper and same ligands?
Aromaticity of [14]annulene - Chemistry Stack Exchange
Feb 17, 2023 · The reason he gave is due to repulsions between hydrogens, the structure is no longer planar But later he told us that [14]annulene is aromatic. But isn't there a repulsion between …
Why is Ni[(PPh₃)₂Cl₂] tetrahedral? - Chemistry Stack Exchange
May 19, 2019 · Since PPh₃ is strong field ligand and, the famous Wilkinson's catalyst, which also possess this ligand is square planar, then what makes the above complex tetrahedral?
Are there square planar complexes with sp2d hybridization?
Aug 26, 2016 · Are there Square Planar complexes in which the outer, vacant d-orbitals take part in hybridization (i.e- are there square planar complexes with sp2d hybridization) ?